Get PHP class namespace dynamically

Answers of > Get PHP class namespace dynamically

Is there a reason the two would behave w3coded namespace name differently, or has dynamic calling for w3coded namespace name namespaces not been implemented in this manor w3coded namespace name yet as this is a new feature? Is there another w3coded namespace name way to dynamically call a class from another w3coded namespace name namespace without explicitly placing its name in w3coded namespace name the code, but from within a variable?,I have an w3coded namespace name object model for the user's type with that name w3coded namespace name defined in the global scope, but I have another w3coded namespace name object with the same name for the user's editor w3coded namespace name in the Editor namespace. For some reason, PHP w3coded namespace name won't allow me to make a namespaced dynamic call w3coded namespace name as follows.,I am generating a dynamic class call w3coded namespace name utilizing a separate class for defining user w3coded namespace name types in my application. Basically the class w3coded namespace name definer takes an integer representation of types w3coded namespace name and interprets them, returning a string w3coded namespace name containing the classname to be called as the w3coded namespace name model for that user., w3coded namespace name 1 w3coded namespace name w3coded namespace name @SDC, better late than never. You can always w3coded namespace name turn a non-fully-qualified namespace into a w3coded namespace name fully-qualified one. The point being that when w3coded namespace name you reference a classname by a string, you must w3coded namespace name always use a fully-qualified namespace. w3coded namespace name – ircmaxell w3coded namespace name Jun 5 '14 at 18:34 w3coded namespace name

Well, just spell out the namespace in the string:

$definition = Definer::defineProfile($_SESSION['user']->UserType);
$class = '\\Editor\\' . $definition;
$foo = new $class();

And if it's a child namespace (as indicated in the comments), simply prepend the namespace with __NAMESPACE__:

$class = __NAMESPACE__ . '\\Editor\\' . $definition;

Current topics : Get PHP class namespace dynamically

Newly Added Questions